A rock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft. write a quadratic function equation that describes the height h at time t.

During upward projection the final velocity is zero, and the gravitational acceleration is - 10 m/s² (against the gravity).

Therefore; using the equation;

S = 1/2gt² + ut

Where s is the height h, g is gravitational acceleration, and t is the time and u is the initial velocity u, is 16 ft/s.

Thus; h = 1/2 (-10) t² + 16t

We get; h = - 5t² + 16t

Therefore; the quadratic equation is 5t² - 16t + h = 0