A canoe is floating down a river with a velocity of 35 meters per minute when it suddenly approaches a waterfall. if the waterfall drop 30 meters, how far put will the canoe land?

From Newton's law v^2 = u^2 + 2as where a is the acceleration and s is the distance.

But to go any further, we need to know how fast the vehicle is accelerating

From v = u + at

We have a = u/t where the final velocity v = 0

So in one minute acceleration = (35 / 60) / 60 = 0.0097 ms/2. The first

experession in bracket is the initial velocity, u, in metres per seconds.

Hence v^2 = (0.583) ^2 + 2 (0.0097) (30)

v^2 = 0.3398 + 0.5826 = 0.9224

v = âš 0.9224 = 0.960m