A 2650-lb car is traveling at sea level at a constant speed. its engine is running at 4500 rev/min and is producing 175 ft-lb of torque. it has a drivetrain efficiency of 90%, a drive axle slippage of 2%, 15 - inch-radius wheels, and an overall gear reduction ratio of 3 to 1. if the car's frontal area is 21.5 ft 2, what is its drag coefficient?

Question

Physics

Dylan Lowe

Today, 01:17

A 2650-lb car is traveling at sea level at a constant speed. its engine is running at 4500 rev/min and is producing 175 ft-lb of torque. it has a drivetrain efficiency of 90%, a drive axle slippage of 2%, 15 - inch-radius wheels, and an overall gear reduction ratio of 3 to 1. if the car's frontal area is 21.5 ft 2, what is its drag coefficient?

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Mya Riggs · Answer 1

The drag coefficient is given by

C = ((F - fW) * 2) / (A*V*V*r)

V = speed of the vehicle = 192.42

f = cofficient of rolling resistance = 0.0231

F = traffic effort = 378

r = density of air = 0.002378

A = frontal area of the vehicle = 21.5

W = weight of the vehicle = 2650

by substituting all the values in the above equation

drag coefficient = C = 0.167