Calculate the number of moles in the 2.00-l volume of air in the lungs of the average person. note that the air is at 37.0ºc (body temperature).

To answer this item, we assume that the air is an ideal gas such that it follows the equation,

PV = nRT

The pressure of the lungs of the person should be in equilibrium to that of the surrounding, making it 1 atm. Substituting the known values to the equation,

n = (1 atm) (2L) / (0.0821 L. atm/mol. K) (37 + 273.15)

n = 0.0785 moles

Answer: 0.0785 moles