Find the peak electric field 1.3 m from a 60-w lightbulb that radiates equally in all directions.

To answer the problem we would be using this formula which is I (peak) = P (peak) / (4πd^2) = 4.24413181578388 w/m^2

E = sqrt (I (peak) * Z0) = 39.9861614728793 V/m

B = µ0*sqrt (I (peak) / Z0) = 1.33379477721328E-7 T

(Free-space impedance Z0 = sqrt (µ0/e0) = 376.730313462204 ohms)