A world war ii bomber flies horizontally over level terrain, with a speed of 273 m/s relative to the ground and at an altitude of 3.27 km. the bombardier releases one bomb. (a) how far does the bomb travel horizontally between its

Given:

u = 273 m/s, horizontal launch speed

h = 3.27 km = 3270 m, altitude.

v = 0, vertical launch speed

g = 9.8 m/s².

Wind resistance is ignored.

The time, t, for the bomb to reach the ground is given by

0t + (1/2) gt² = h

4.9t² = 3270

t² = 667.3469

t = 25.833 s

The horizontal distance traveled is

273*25.833 = 7052.4 m = 7.0524 km

Answer: 7.05 km