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5 February, 13:55

A world war ii bomber flies horizontally over level terrain, with a speed of 273 m/s relative to the ground and at an altitude of 3.27 km. the bombardier releases one bomb. (a) how far does the bomb travel horizontally between its

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  1. 5 February, 15:39
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    Given:

    u = 273 m/s, horizontal launch speed

    h = 3.27 km = 3270 m, altitude.

    v = 0, vertical launch speed

    g = 9.8 m/s².

    Wind resistance is ignored.

    The time, t, for the bomb to reach the ground is given by

    0t + (1/2) gt² = h

    4.9t² = 3270

    t² = 667.3469

    t = 25.833 s

    The horizontal distance traveled is

    273*25.833 = 7052.4 m = 7.0524 km

    Answer: 7.05 km
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