A bullet is fired horizontally with an initial velocity of 144.7 m/s from a tower 11 m high. if air resistance is negligible, what is the horizontal distance the bullet travels before hitting the ground?

H = 11 m, the vertical distance that the bullet falls.

Initial vertical velocity = 0

Horizontal velocity = 144.7 m/s

The time, t, taken to fall 11 m is given by

(1/2) * (9.8 m/s²) * (t s) ² = (11 m)

4.9t² = 11

t = 1.4983 s

If aerodynamic resistance is ignored, the horizontal distance traveled before the bullet hits the ground is

d = (144.7 m/s) * (1.4983 s) = 216.8 m

Answer: 216.8 m