Imagine you have just witnessed a small avalanche on a mountain while skiing, and two slushy snowballs just crashed together in a perfectly inelastic collision. They are moving as one larger snowball, as a combined mass. Before the collision, snowball A was 7 kg and had initial momentum of - 14 kg · m/s; therefore, its velocity must have been? m/s

Snowball B had initial momentum of 15 kg ∙ m/s, and a velocity of 5 m/s; therefore, its mass must have been? kg.

Recognizing that momentum is conserved in inelastic collisions, the total momentum of the combined snowballs after the collision must be? kg · m/s.

Question

Physics

Lamar Lloyd

28 October, 18:29

Imagine you have just witnessed a small avalanche on a mountain while skiing, and two slushy snowballs just crashed together in a perfectly inelastic collision. They are moving as one larger snowball, as a combined mass. Before the collision, snowball A was 7 kg and had initial momentum of - 14 kg · m/s; therefore, its velocity must have been? m/s

Snowball B had initial momentum of 15 kg ∙ m/s, and a velocity of 5 m/s; therefore, its mass must have been? kg.

Recognizing that momentum is conserved in inelastic collisions, the total momentum of the combined snowballs after the collision must be? kg · m/s.

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Answers (2)

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Salvador Mccann · Answer 1

We have that the momentum p is given by the formula p=mv where m is the mass and v is the velocity. Since for A p=-14kgm/s and m=7, we have that the velocity is - 14/7=-2m/s. Hence its speed is 2 m/s.

For b we have that p=15kgm/s and v=3m/s. Because m=p/v, we have m=3kg.

We also have that the momentum is conserved in this system. Hence, the net sum of the momentum of the 2 snowballs equals the momentum of the single giant ball. Hence, p (total) = p (combined) = - 14+15=1kgm/s (momentum is a vector; the positive sign means that it tends to the positive direction).

Cale Schultz · Answer 2

The first is - 2.

the second is 3.

the third is 1.