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16 March, 17:32

A swimming pool contains x (less than 0.02) grams of chlorine per cubic meter. the pool measures 5 meters by 50 meters and is 2 meters deep. some water will be drained and replaced by water contain 5 grams of chlorine per cubic meter. how much water should be drained so the pool ends up with 0.02 grams of chlorine per cubic meter.

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  1. 16 March, 18:07
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    The solution for this problem would be: (10 - 500x) / (5 - x)

    so start by doing:

    x (5*50*2) - xV + 5V = 0.02 (5*50*2)

    500x - xV + 5V = 10

    V (5 - x) = 10 - 500x

    V = (10 - 500x) / (5 - x)

    (V stands for the volume, but leaves us with the expression for x)
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