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4 November, 14:27

A boy jumps at a speed of 20.0 m/s at an angle of 25.0o above the horizontal. what is the horizontal component of the boy's velocity?

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  1. 4 November, 17:22
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    Given:

    Launch velocity = 20 m/s

    Launch angle = 25° above he horizontal.

    The horizontal component of velocity is by definition

    Vx = 20*cos (25°) = 18.13 m/s

    Answer: 18.13 m/s (nearest hundredth)
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