Calculate the buoyant force due to the surrounding air on a man weighing 700 n. assume his average density is the same as that of water. suppose that the density of air is 1.20 kg/m3. express your answer to two significant figures and include the appropriate units.

The buoyant force is represented by the weight of the air which is displaced by the body.

The weight of the displaced air can be calculated using the following rule:

weight of displaced air = (density) (volume) (gravitational force)

where "volume" is the volume of the body (the man in our case) and density is the density of air ( = 1000 kg/m^3)

So, we need to calculate the volume of the man:

weight = gravitational force x volume

700 n = 9.8 x volume

Therefore, volume of man = 71.428 m^3

Substituting with this volume along with the gravitational force and density in the above equation, we can calculate the buoyant force as follows:

buoyant force = weight of air displaced = (1000) (71.428) (9.8)

= 669.9944 x 10^3 n