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Q1=0,07Mc Q2=2C r=1,08 cm F = ... ?

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  1. Arianny
    The force (F) of attraction or repulsion between two point charges (Q1 and Q2) is given by the following rule:

    F = (k * q1 * q2) / (r^2) where:

    q1 and q2 are the charges

    k is coulomb's constant = 9 x 10^9 N. m 2 / C 2

    r is the distance between the two charges.

    Applying the givens in the mentioned equation, we find that:

    F = (9 x 10^9 x 0.07 x 10^6 x 2) / (0.0108) ^2 = 1.08 x 10^19 n
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