From the top of a cliff, a person tosses a pebble straight downward with an initial velocity of - 9.0 meters/second. After 0.50 seconds, how far beneath the cliff is the pebble?

a) - 2.0

b) - 3.9

c) - 5.7

d) - 10.3

Question

Physics

Raven Serrano

21 November, 22:26

From the top of a cliff, a person tosses a pebble straight downward with an initial velocity of - 9.0 meters/second. After 0.50 seconds, how far beneath the cliff is the pebble?

a) - 2.0

b) - 3.9

c) - 5.7

d) - 10.3

+1

Answers (1)

Know the Answer?

Wyatt Guzman · Answer 1

Y - yo = Vo*t - g * (t^2) / 2

Vo = - 9.0 m/s

t = 0.50 s

=> y - yo = - 9.0 m/s * 0.5 s - 9.8 m/s^2 * (0.5s) ^2 / 2 = - 4.5m - 1.225m = - 5.725 m.

Answer: option c) - 5.7

From the top of a cliff, a person tosses a pebble straight downward with an initial velocity of - 9.0 meters/second. After 0.50 seconds, how far beneath the cliff is the pebble?a) - 2.0b) - 3.9c) - 5.7d) - 10.3

From the top of a cliff, a person tosses a pebble straight downward with an initial velocity of - 9.0 meters/second. After 0.50 seconds, how far beneath the cliff is the pebble?

a) - 2.0

b) - 3.9

c) - 5.7

d) - 10.3