Ask Question
21 November, 22:26

From the top of a cliff, a person tosses a pebble straight downward with an initial velocity of - 9.0 meters/second. After 0.50 seconds, how far beneath the cliff is the pebble?

a) - 2.0

b) - 3.9

c) - 5.7

d) - 10.3

+1
Answers (1)
  1. 21 November, 23:41
    0
    Y - yo = Vo*t - g * (t^2) / 2

    Vo = - 9.0 m/s

    t = 0.50 s

    => y - yo = - 9.0 m/s * 0.5 s - 9.8 m/s^2 * (0.5s) ^2 / 2 = - 4.5m - 1.225m = - 5.725 m.

    Answer: option c) - 5.7
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “From the top of a cliff, a person tosses a pebble straight downward with an initial velocity of - 9.0 meters/second. After 0.50 seconds, ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers