A forcue of 186 N acts on a 7.3-kg bowling ball for 0.40 s. what is the chanhe in velocity of the bowling ball

Given are: Force = 186 N; Mass = 7.3 Kg; time = 0.40 s Initial Velocity Vi = 0

Final Velocity Vf = ?

Unknown: Change in velocity or acceleration

F = ma; but a = Vf - Vi/t Solve for Vf or Final velocity

therefor F = m (Vf-Vi/t) Ft = m (Vf - Vi/t) But Vi = 0

Vf = (186 N) (0.40 S) / 7.3 Kg answer Vf = 10.2 m/s

Solving for acceleration or change in velocity

a = Vf - Vi/t

a = 10.2 m/s - 0/0.4s therefore change in velocity a = 25.5 m/s²

As we know that Force = mass * acceleration.

Here a force of 186 N acting on 7.3 kg ball will create acceleration = 186/7.3 = 25.48 m/s2

Also, change in velocity can be found as, acceleration multiplied by time it is acting on object.

Therefore, change in velocity = 24.48 * 0.4 = 10.19 m/s