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3 December, 18:20

A hypothetical spherical planet consists entirely of iron. what is the period of a satellite that orbits this planet just above its surface?

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  1. 3 December, 20:16
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    Newton states: F=G*M*m / r^2, where M = ρ * (4/3) * pi*r^3 is mass of iron planet, r is radius of the planet;

    the same gravity force F=m*w^2*r is the centripetal force for the orbiting satellite, where angular speed w=2pi/T, T is period;

    thus F=F; G*M*m / r^2 = m*w^2*r; or;

    G * (ρ * (4/3) * pi*r^3) / r^2 = (2pi/T) ^2*r; or;

    G*ρ/3 = pi/T^2, hence T = √ (3pi / (G*ρ)) =

    = √ (3pi / (6.6742E-11 * 7860)) = 4238.62s = 70h 38’;
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