How much heat is absorbed by a 29g iron skillet when its temperature rises from 9oC to 105oC?

We have:

Mass (m) of the iron skillet = 29 grams

Difference in temperature (Δt) = 105 - 9 = 96°C

Heat capacity of iron = 0.449 J/g °C

The energy (Q) is given by:

Q = m * Δt * specific heat

Q = 29 grams * 96 °C * 0.449 J/g°C

Q = 1250.016 Joules