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7 August, 21:08

Suppose you pour water into a container until it reaches a depth of 21 cm. next, you carefully pour in a 11-cm thickness of olive oil so that it floats on top of the water. what is the pressure at the bottom of the container? (express your answer to four significant digits.)

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  1. 8 August, 00:50
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    3040. Pascals. The density of olive oil is 0.911 g/cm^3 and the density of water is 1.000 g/cm^3. To calculate the pressure of 1 cm of water, 1000 kg/m^3 * 9.8 m/s^2 * 0.01 m = 98.000 Pa To calculate the pressure of 1 cm of olive oil 911 kg/m^3 * 9.8 m/s^2 * 0.01 m = 89.278 Pa Now to calculate the pressure at the bottom of the container, simply add the products of how many cm of each fluid you have. So 21 * 98.000 Pa + 11 * 89.278 Pa = 2058 Pa + 982.058 Pa = 3040.058 Pa So the pressure at the bottom of the container will be 3040. Pascals.
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