Ask Question
12 December, 13:48

One end of a rope is tied to the handle of a horizontally-oriented and uniform door. a force fis applied to the other end of the rope as shown in the drawing. the door has a weight of 145 n and is hinged on the right. what is the maximum magnitude of ffor which the door will remain at rest?

+3
Answers (1)
  1. 12 December, 17:26
    0
    Answer:The weight of the door creates a CCW torque given by Tccw = 145 N*3.13 m / 2 You need a CW torque that's equal to that Tcw = F*2.5 m*sin20
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “One end of a rope is tied to the handle of a horizontally-oriented and uniform door. a force fis applied to the other end of the rope as ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers