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23 August, 13:34

G 1470-kilogram truck moving with a speed of 24.0 m/s runs into the rear end of a 1110-kilogram stationary car. if the collision is completely inelastic, how much kinetic energy is lost in the collision?

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  1. 23 August, 16:50
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    Kinetic energy = Potential energy

    (1/2) mV^2 = mgh

    where

    m = mass of the car

    V = velocity of the car = 15 m/s (given)

    g = acceleration due to gravity = 9.8 m/sec^2 (constant)

    h = vertical distance travelled by car = d (sin 19)

    d = distance travelled by the car along the incline

    Substituting values,

    (1/2) (m) (529) = m (9.8) h

    and since "m" appears on both sides of the equation, it will simply cancel out, hence the above becomes

    (1/2) (529) = 9.8h

    h = 225/19.6 = 26,98 m

    Let

    d = distance that the car will coast up the hill before coming down

    h/d = sin 19

    and therefore,

    d = h/sin 19

    and substituting values,

    d = 26,98/sin 19

    d = 82,870 m - - - after coasting up the hill for this distance, the car will start to roll down.
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