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25 June, 12:14

Water flows over a section of niagara falls at a rate of 6.00 ' 105 kg/s and falls 50.0 m. what is the power dissipated by the waterfall?

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  1. 25 June, 13:13
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    The answer is: PE lost every second = mgh = 1.2x10^6 * 9.81 * 50 = 5.89x10^8J So, Power = 5.89x10^8W
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