A load absorbs s = 28 kva at a leading power factor of pf = 0.79. use this information to calculate the average (p) and reactive (q) power for the load. enter comma separated numerical answers with three significant figures.

Power factor (PF) = Average power (kW) / Apparent power (kVA)

From the information given;

0.79 = Average power/28

Average power = 28*0.79 = 22.12 kW

Reactive power (kVAR) = Sqrt (Apparent power^2 - Average power^2) = 9Sqrt (28^2 - 22.12^2) = 17.17 kVAR

Answers: 22.12 kW, 17.17 kVAR