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17 June, 13:25

What is the speed of a proton whose kinetic energy is 3.4 kev?

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  1. 17 June, 13:52
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    The kinetic energy of the proton is 3.4 kev

    1 kev = 1.602 * 10^-16 joules

    therefore 3.4 kev is equivalent to;

    3.4 * (1.602 * 10^-16) = 5.4468 * 10^-16 J

    Kinetic energy is calculated by the formula 1/2mv² where m is the mass and v is the velocity.

    Therefore V = √ ((2 * (5.4468*10^-16)) / (1.67 * 10^-27))

    = 8.077 * 10^5 m/s
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