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24 September, 04:51

A ball is thrown straight up it passes a 2.00 m high window 7.5 meters off the ground on its path up it takes 1.3 s to go past the window. what was the balls initial velocity?

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  1. 24 September, 08:14
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    Let's say the velocity at the bottom of the window was "v."

    s = v*t + ½at²

    2 m = v * 1.3s - 4.9m/s² * (1.3s) ² = v * 1.3s - 8.3 m

    v = 10.3m / 1.3s = 7.9 m/s

    Then the initial speed was

    V = √ (v² + 2as) = √ (7.9m/s² + 2 * 9.8m/s² * 7.5m) = 14 m/s ◄ initial velocity

    (after rounding to 2 digits from 14.5 m/s).
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