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31 January, 02:10

A box of mass 14 kg sits on an inclined surface with an angle of 52degrees. What is the component of the weight of the box along the surface?

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  1. 31 January, 03:41
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    First, we calculate for the weight of the object by multiplying the given mass by the acceleration due to gravity which is equal to 9.8 m/s²

    Weight = (14 kg) (9.8 m/s²)

    Weight = 137.2 N

    The component of the weight that is along the surface of the inclined plane is equal to this weight times the sine of the given angle.

    Weight = (137.2 N) (sin 52°)

    weight = 108.1 N
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