What is the pressure of a 59.6-l gas sample containing 3.01 mol of gas at 44.9°c? (r = 0.0821 l • atm / (k • mol), 1 atm = 760 torr) ?

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Physics

Annika Braun

3 December, 05:34

What is the pressure of a 59.6-l gas sample containing 3.01 mol of gas at 44.9°c? (r = 0.0821 l • atm / (k • mol), 1 atm = 760 torr) ?

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Kendall Floyd · Answer 1

Presuming that the gas behaves like an ideal gas: Volume in cubic meter V = 59.6x 0.001 = 0.0596 mÂł n=3.01 mol Temperature in Kelvin T=44.9+273.15=318.05 K R = 8.413 J / mol K The ideal gas law: PxV = nxRxT Substituting the give information from the question into the ideal gas law: P = 3.01 mol x 8.413 J/mol k x 318.05 K / 0.0596 = 133544.392 Pa 1351.3458 Pa / 101325 Pa / atm = 1.3179806 atm