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3 March, 02:54

A 2300 kg truck has put its front bumper against the rear bumper of a 2500 kg suv to give it a push. with the engine at full power and good tires on good pavement, the maximum forward force on the truck is 18,000 n.

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  1. 3 March, 04:41
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    F=ma

    m=total mass = 2300kg+2500kg=4800

    F=18000N

    a=?

    a=F/m

    a=18000/4800

    a=3.8m/s^2

    Final answer
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