Two vectors are presented as a=3.0i + 5.0j and b=2.0i+4.0j find (a) a x b, ab (c) (a+b) b and (d) the component of a along the direction of

b.

Let's ask this question step by step:

Part A)

a x b = (3.0i + 5.0j) x (2.0i + 4.0j) = (12-10) k = 2k

ab = (3.0i + 5.0j). (2.0i + 4.0j) = 6 + 20 = 26

Part (c)

(a + b) b = [ (3.0i + 5.0j) + (2.0i + 4.0j) ]. (2.0i + 4.0j)

(a + b) b = (5.0i + 9.0j). (2.0i + 4.0j)

(a + b) b = 10 + 36

(a + b) b = 46

Part (d)

comp (ba) = (a. b) / lbl

a. b = (3.0i + 5.0j). (2.0i + 4.0j) = 6 + 20 = 26

lbl = root ((2.0) ^ 2 + (4.0) ^ 2) = root (20)

comp (ba) = 26 / root (20)

answer

2k

26

46

26 / root (20)