Ask Question
12 November, 02:20

Calculate the tension in qa horizontal string that whirls a 2-kg toy in a circle of radius 2.5 m when it moves at 3 m/s on an icy surface.

+3
Answers (1)
  1. 12 November, 02:25
    0
    To keep the object swirling, it should be that the forces are balanced in the system. The tension in the spring should be equal to the force exerted by the object in the circular motion. So,

    Tension = Force by the object in circular motion

    where the force is given by Newton's second law of motion

    F = ma

    Acceleration for a circular motion is the squared of the velocity over the radius of the motion.

    F = m (v^2) / r

    Thus, tension would be

    Tension = mv^2 / r

    Tension = 2 kg (3 m/s) ^2 / 2.5 m

    Tension = 7.2 kg m/s^2 or 7.2 N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Calculate the tension in qa horizontal string that whirls a 2-kg toy in a circle of radius 2.5 m when it moves at 3 m/s on an icy surface. ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers