Ask Question
27 June, 23:15

A long, thin rod parallel to the y-axis is located at x=-1.0 cm and carries a uniform linear charge density of + 1.0 nc/m. a second long, thin rod parallel to the z-axis is located at x=+1.0 cm and carries a uniform linear charge density of - 1.0 nc/m. what is the net electric field due to these rods at the origin? (ϵ0=8.85*10-12 c2/n · m2)

+2
Answers (1)
  1. 28 June, 01:51
    0
    These long thin rods are essentially just infinite lines of charge, through gauss' law, we can get the electric field for an infinite line of charge to be E = 2Kλ/r, where E is the electric field, K is the electrostatic constant (same as 1 / (4πε₀) = 9*10⁹), λ is the linear charge density and r is the distance we are from the line of charge. We'll have 2 of these terms, one for each line of charge. Both lines of charge are 1 cm from the origin, so the r's drop out. Then one has a + 1 linear charge density and one has a - 1 linear charge density. The 2 and the K are constants and won't matter, so we have the electric field cancel out and we get an E field of 0 at the origin. Math looks like this E = 2Kλ/r + 2Kλ/r = 2K (+1) / (1) + 2K (-1) / (1) = 2K - 2K = 0
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A long, thin rod parallel to the y-axis is located at x=-1.0 cm and carries a uniform linear charge density of + 1.0 nc/m. a second long, ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers