How far does a plane fly in 15 s while its velocity is changing from 145 m/s to 75 m/s at a uniform rate of acceleration?

The solution would be like this for this specific problem:

Given:

- The initial velocity of the plane u = 75 m / s

- Duration of change in velocity t = 15 s

- The final velocity of the plane after 15 s, v = 145 m / s

- Let its uniform acceleration be am s ^-2

Now we know that v = u + at ⇒.145 = 75 + a * 15

⇒ a = (145) / 15 = 14/3 m s ^-2

Now distance traversed during 15s is:

s = u * t + 1/2 * a * t ^2 = 75 * 15 + ½ * 14/3 * 15 ^2 = 1650 m