A ball is thrown straight upward with a velocity of 24m/s How much time passes before the ball strikes the ground? Disregard air resistance.

Knowing that when you throw something in the air, the speed will be 0m/s.

The acceleration due to gravity is 9.8m/s^2.

v2=0

v1=24

a=9.8

The formula is:

v2=v1+a (t)

v2-v1/a=t

0-24/9.8

24m/s/9.8m/s^2=t (You can choose which direction is positive and negative)

2.45s=t

t=2.45*2s (Since you calculate both going up and down)

t=4.9s