If a glass is knocked off of a table that is 1.4m tall, how long does it take for the glass to hit the ground?

H = 1.4 m, the height the glass falls.

u = 0, initial vertical velocity, because the glass is knocked off a table.

Assume g = 9.8 m/s², and ignore air resistance.

Let t = the time for the glass to hit the ground.

Then

(1/2) * (9.8 m/s²) * (t s) ² = (1.4 m)

4.9t² = 1.4

t² = 0.2857

t = 0.5345 s

Answer: 0.54 s (nearest hundredth)