Ask Question
4 May, 08:26

A man weighing 750 n and a woman weighing 500 n have the same momentum. what is the ratio of the man's kinetic energy km to that of the woman kw?

+4
Answers (1)
  1. 4 May, 09:30
    0
    Because weight W = M g, the ratio of weights equals the ratio of masses.

    (M_m g) / (M_w g) = [ (p^2 Man) / (2 K_man) ] / [ (p^2 Woman) / (2 K_woman)

    but p's are equal, so

    K_m/K_m = (M_w g) / (M_m g) = W_woman / W_man = 450/680 = 0.662
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A man weighing 750 n and a woman weighing 500 n have the same momentum. what is the ratio of the man's kinetic energy km to that of the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers