How much heat is absorbed by a 39g iron skillet when its temperature rises from 15oC to 24oC?

To begin, your equation is Q=mc{triangle}T

Q is the end heat in Joules

m is the mass

c is the specific heat

and

{triangle} T is the change in temperature

Now that we have the equation down, we are trying to find the end heat.

Your specific heat, I suspect is 0.450 J/g{degrees}C because its the specific heat of iron. Making your equation you'll get:

Q = (39g) x (0.450 J/g{degrees}C) x (9{degrees}C)

Multiplying it all you'll get:

Q = 157.95J

or

157.95 Joules