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6 December, 07:41

A basketball referee tosses the ball straight up for the starting tip-off. at what velocity (in m/s) must a basketball player leave the ground to rise 1.23 m above the floor in an attempt to get the ball?

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  1. 6 December, 10:58
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    The formular for solving this equation is

    mgh = mv^2/2

    The M on both sides of the equation stand for mass and the two of them cancel each other out and the equation becomes:

    gh = V^2 / 2

    g = 9.8 m/s

    h = 1.23 m

    V?

    V is the velocity that we need to find, so we are going to make V the subject of the formular:

    V = Square root of 2gh = square root of [2 * 9.8 * 1.23] = square root of [24.108] = 4.9

    Thus, the velocity = 4.90 m/s
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