Subtitle is the half-life of an element is 10 years how many half-lives will it take before only about 6% of the original sample remains

We can solve this problem by using the equation

as shown: A=Aoe^ - (ln2/t) T where A is the final amount (0.06 gram), Ao is

the initial amount (1g * assumed), t is the half-life (10 years) and lastly T

time elapsed (required). Plug in the values in the equation and you should

get 40.5 years and this is approximately 4 half-lives.