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16 December, 11:40

A 2.0 kilogram ball rolling along a flat surface starts up a hill. If the ball reaches a height of 0.63 meters, what was its initial speed

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  1. 16 December, 13:39
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    The potential energy as it reaches a height of 0.63 meters is mgh

    Since total mechanical energy is conserved, Set that equal to the initial kinetic energy which is 0.5mv^2

    2*9.8*0.63 = 0.5*2*v^2

    12.348 = v^2

    3.51 = v

    That's it's initial speed.
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