For the reaction a → b, the rate law is: rate = k * [a]. over the course of 4 minutes, the concentration of a reduces by one-half, from 1.00 mto 0.50 m. how is the rate affected?

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Physics

Kirsten

Yesterday, 23:48

For the reaction a → b, the rate law is: rate = k * [a]. over the course of 4 minutes, the concentration of a reduces by one-half, from 1.00 mto 0.50 m. how is the rate affected?

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Arnold · Answer 1

The rate law for the equation is as follows;

Rate = k [A]

the order with respect to A is 1, therefore this is a first order reaction as A is the only reactant.

At t = 0 minutes [A] = 1.00 M

rate - initial rate

rate = k [1.00 M] - - - 1)

At t = 4 minutes [A] = 0.50 M

rate' - new rate

rate' = k [0.50] - - 2)

Divide 2) / 1)

rate'/rate = 0.5/1

rate' = 0.5 rate

rate has been reduced by half