How many electrons must be removed from an electrically neutral silver dollar to give it a charge of + 2.4 μC?

The total charge to be removed is - 2.4 μC. The number of

electrons corresponding to this charge is

N = (-2.4 x 10^-6 C) / (-1.60 x 10^-19 C)

= 1.5 x 10^13 electrons

Therefore 1.5 x 10^13 electrons need to be removed from the neutral silver dollar.