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4 November, 00:57

How many lines/cm should be present in a diffraction grating to produce the first bright fringe at an angle of 4o when yellow light of wavelength 580 nm passes through it?

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  1. 4 November, 04:00
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    Wavelength lambda = 580nm = 580 x 10^-9 m

    Angle = 40 degres

    Diffraction order n = 1

    Space between the lines is d

    Number of lines = 1 / d

    Equation for the diffraction which is 2 x d x sin theta = n x lambda

    => d = lambda / (2 x sin theta) = 580 x 10^-9 / 1.285 = 4.51 x 10^-7

    Number of lines = 1 / 4.51 x 10^-7 = 0.221 x 10^7 = 2.2 x 10^6 lines / meter

    Lines per centimeter = 22000 lines/cm
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