Ask Question
2 August, 21:39

A rod is lying on the top of a table. one end of the rod is hinged to the table so that the rod can rotate freely on the tabletop. two forces, both parallel to the tabletop, act on the rod at the same place. one force is directed perpendicular to the rod and has a magnitude of 37.8 n. the second force has a magnitude of 56.5 n and is directed at an angle θ with respect to the rod. if the sum of the torques due to the two forces is zero, what must be the angle θ?

+4
Answers (1)
  1. 2 August, 23:28
    0
    The solution for this problem is:

    For the torques to be equivalent the constituent of the forces vertical to the rod must be equal and in the opposite direction

    So 37.8 = 56.5 * sin (θ)

    So θ = arc sin (37.8/56.5)

    = arcsin 0.670212766 = sin⁻¹ 0.670212766 = 42° 5' 0.558"

    = 42.08348831° + k*360° (k = ... - 1,0,1, ...)

    = - 317.91651169°, 42.08348831°, 402.08348831°, ...

    = 0.73449543rad + k*2π (k = ... - 1,0,1, ...)

    = - 1.76620284π, 0.23379716π, 2.23379716π, ...

    = 42.1 degrees
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A rod is lying on the top of a table. one end of the rod is hinged to the table so that the rod can rotate freely on the tabletop. two ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers