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19 September, 03:22

A projectile is shot from the surface of earth by means of a very powerful cannon. if the projectile reaches a height of 100.0 km above earth's surface, what was the speed of the projectile when it left the cannon?

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  1. 19 September, 06:32
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    The relevant formula we can use in this case is:

    v^2 = v0^2 + 2 a d

    where,

    v = final velocity = 0

    v0 = initial velocity = ?

    a = acceleration = - 9.8 m/s^2 (negative since opposite)

    d = 100 km = 100,000 m

    0 = v0^2 + 2 (-9.8) (100,000)

    v0 = 1400 m/s
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