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3 March, 12:56

Rank in order, from smallest to largest, the six torques (torque 1 to torque 2) about the hinge.?

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  1. 3 March, 14:26
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    The solution for this problem is:torque1 = torque2 = FL / 2

    Torque 3 = Torque 4 = FL / 2 * sin (theta)

    Torque 5 = 2 FL

    Torque 6 = 0

    So the order of the torques from smallest to largest is torque 6, (torque 3 and 4), (torque 1 and 2), torque 5.

    Remember or just take note that sin (theta) < 1 is why 3 and 4 are less than 1 and 2.
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