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27 August, 19:19

Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 164 v.

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  1. 27 August, 20:03
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    Work done in moving a proton = potential difference*Charge of a proton

    = 164*1.6*10⁻¹⁹ = 2.624*10⁻¹⁷ J

    This work done should be equal to change in kinetic energy.

    Initial speed of proton is zero therefore K. E initial will be zero.

    Work done = final kinetic energy = 2.624*10⁻¹⁷ J

    K. E = mv²/2

    v² = 2 (2.624*10⁻¹⁷) / 1.6*10⁻²⁷ = 3.28*10¹⁰ m/s

    ∴ v = 1.811*10⁵ m/s
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