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16 July, 04:46

Two charged particles are placed 2.0 meters apart. The first charge is + 2.0 E-6 C, and the second charge is + 4.0 E-6 C. What is the electrical force between the two charges?

(k = 9.0 E9 Nm^2/c^2)

A. + 1.8 E-2 N and it is repulsive

B. + 3.6 E-2 N and it is repulsive

C. + 4.5 E-2 N and it is attractive

D. + 9.0 E - 2 N and it is attractive

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Answers (1)
  1. 16 July, 06:51
    0
    F = kq1q2/r^2

    q1 is first charge

    q2 is second charge

    k is 9 E9

    r is distance between them

    F = (9E9) (2 E-6) (4 E-6) / 2^2 = 0.018 N

    A postive answer indicates a repulsive force
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