Two charged particles are placed 2.0 meters apart. The first charge is + 2.0 E-6 C, and the second charge is + 4.0 E-6 C. What is the electrical force between the two charges?

(k = 9.0 E9 Nm^2/c^2)

A. + 1.8 E-2 N and it is repulsive

B. + 3.6 E-2 N and it is repulsive

C. + 4.5 E-2 N and it is attractive

D. + 9.0 E - 2 N and it is attractive

Question

Physics

Carlen

16 July, 04:46

Two charged particles are placed 2.0 meters apart. The first charge is + 2.0 E-6 C, and the second charge is + 4.0 E-6 C. What is the electrical force between the two charges?

(k = 9.0 E9 Nm^2/c^2)

A. + 1.8 E-2 N and it is repulsive

B. + 3.6 E-2 N and it is repulsive

C. + 4.5 E-2 N and it is attractive

D. + 9.0 E - 2 N and it is attractive

+5

Answers (1)

Know the Answer?

Dennis Leblanc · Answer 1

F = kq1q2/r^2

q1 is first charge

q2 is second charge

k is 9 E9

r is distance between them

F = (9E9) (2 E-6) (4 E-6) / 2^2 = 0.018 N

A postive answer indicates a repulsive force