Find the magnitude of the gravitational force a 68.4 kg person would experience while standing on the surface of earth with a mass of 5.98 Ã 1024 kg and a radius of 6.37 Ã 106 m. the universal gravitational constant is 6.673 Ã 10â11 n Â· m2 / kg2. answer in units of n.

Question

Physics

Genesis Ellison

10 January, 09:27

Find the magnitude of the gravitational force a 68.4 kg person would experience while standing on the surface of earth with a mass of 5.98 Ã 1024 kg and a radius of 6.37 Ã 106 m. the universal gravitational constant is 6.673 Ã 10â11 n Â· m2 / kg2. answer in units of n.

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Kane Wheeler · Answer 1

Given: Mass of a person M = 68.4 Kg.

Mass of earth Me = 5.98 x 10²⁴ Kg

Radius of earth r = 6.37 x 10⁶ m

G = 6.67 x 10⁻¹¹ N. m²/Kg²

Required: F = ?

Formula: F = GMeM/r²

F = (6.67 x 10⁻¹¹ N. m²/Kg²) (5.98 x 10²⁴) (68.4 Kg) / (6.37 x 10⁶ m) ²

F = 672.41 N