Javelin at 72 meters/second. he throws it at an angle of 22 degrees. how fast is he throwing it in the x-direction in meters/second?

Question

Physics

Linda

29 December, 21:29

Javelin at 72 meters/second. he throws it at an angle of 22 degrees. how fast is he throwing it in the x-direction in meters/second?

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Sam · Answer 1

Assume this is 22 degrees from the horizontal (x).

A vector can always be split into components - in this case we can think of the world in two dimensions, meaning the 72ms-1 has a vertical and a horizontal component. We therefore know the hypotenuse of the triangle (the overall velocity) and the angle from the ground. Hence we can use trigonometry to solve this problem.

We know x and the hypotenuse, and we want to know the magnitude of the adjacent side (horizontal), therefore we can use cosx=adj/hyp

Substituting:

Cos (22) = adj/72

Adj = 72cos22 = 66.8ms-1 = 67ms-1 to 2sf