The upper end of a 3.80-m-long steel wire is fastened to the ceiling, and a 54.0-kg object is suspended from the lower end of the wire. you observe that it takes a transverse pulse 0.0492 s to travel from the bottom to the top of the wire. what is the mass of the wire?

Question

Physics

Skylar Mckay

5 January, 14:20

The upper end of a 3.80-m-long steel wire is fastened to the ceiling, and a 54.0-kg object is suspended from the lower end of the wire. you observe that it takes a transverse pulse 0.0492 s to travel from the bottom to the top of the wire. what is the mass of the wire?

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Answers (1)

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Evan Gilmore · Answer 1

Given that the lenth write steel l = 3.80m fastened celling mass m = 54.0kg

v = s/t

v = 3.8/0.0492

v = 77.23 m/s

now, the formula for speed in a wire is

v = (T/ÎĽ) ^1/2

where T is the tension in the string and ÎĽ is the mass pee unit length.

v = (Tl/m) ^1/2 ... (replace ÎĽ with m/l)

now T = 550N

v = [ 550 (3.8) / m ]^1/2

squaring both sides

v^2 = 550 (3.8) / m

v^2 = 2090/m

putting the value of v calculated above and solving

m = 0.35 kg