A cube has a drag coefficient of 0.8. what would be the terminal velocity of a sugar cube 1 cm on a side in air (ρ = 1.2 kg/m3) ? take the density of sugar to be 1.6 x 103 kg/m3.

To answer this question, we should know the formula for the terminal velocity. The formula is written below:

v = √ (2mg/ρAC)

where

m is the mass

g is 9.81 m/s²

ρ is density

A is area

C is the drag coefficient

Let's determine the mass, m, to be density*volume.

Volume = s³ = (1 cm*1 m/100 cm) ³ = 10⁻⁶ m³

m = (1.6*10³ kg/m³) (10⁻⁶ m³) = 1.6*10⁻³ kg

A = (1 cm * 1 m/100 cm) ² = 10⁻⁴ m²

v = √ (2*1.6*10⁻³ kg*9.81 m/s²/1.6*10³ kg/m³*10⁻⁴ m²*0.8)

v = 0.495 m/s