An object is dropped from a platform 400 ft high. ignoring wind resistance, what will its speed be when it reaches the ground?

To answer this item, we first convert the given height in meters.

height = (400 ft) x (1 m / 3.28 ft) = 121.95 m

Then, use the equation of motion which relates the distance covered with the initial and final velocities and the acceleration which takes a form,

2ad = Vf² - Vi²

Substituting the known values from the given,

2 (9.8 m/s²) (121.95 m) = Vf² - 0²

The value of Vf from the equation is 48.89 m/s.

If we are to convert this back to feet.

speed = (48.89 m/s) (3.28 ft/1 m) = 160.35 ft/s

Answer: 160.35 ft/s